The modified area is (1/48) (2πr(4h+3r))
<u>Step-by-step explanation:</u>
Let the radius be 'r' and height be 'h'.
Area of cylinder= 2π r(h+r)
The radius is shrunk down to quarter of its original radius
r = r/4
The height is reduced to a third of its original height
h = h/3
New Area = 2π(r/4) [(h/3) +(r/4) ]
= (1/4)2πr[(4h+3r) /12]
= (1/48) (2πr(4h+3r))
The answer is <span>10 units
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The diameter of the cylinder (d) is the twice of its radius (r): d = 2r
The volume (V) of the cylinder with radius r and height h is:
V = π r² h
We have:
d = 2r
r = ?
h = 7
π = 3.14
V = 175π
175π = π * r² * 7
175 = r² * 7
r² = 175/7
r² = 25
r = √25
r = 5
d = 2r
d = 2 * 5
d = 10
Answer:
Negative
Step-by-step explanation:
the slope in this equation is negetive as it is pointing in a downwards position.
Zero would be horizontal, undefined would be vertical and positive would be going in an upwards motion
Answer:
D: (0,3)
Step-by-step explanation:
Answer:
here i hope this help im not sure if a can find the exact answer your looking for but here is a formula
