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3 years ago

The diameter of a circle is 20m Find the circumference to the nearest tenth

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

8 0

Answer:

C = 62.8 m

Step-by-step explanation:

The circumference formula is C = πd.

Here d = 20 m. Therefore, the circumference of this circle is C = (20 m)π.

To the nearest 10th, we round off C = (20 m)(3.14159) = C = 62.8 m

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3 years ago

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Angelica earns d dollars for babysitting each week. She also receives an allowance of $10 per week. The expression (10+d)∙5 can

Katyanochek1 [597]

Answer:

The amount of money Angelica will have at the end of five weeks if d = $25 is $175.

Step-by-step explanation:

The given information are;

The allowance Angelica earns for baby sitting = d dollars per week

The amount she receives as allowance = $10 per week

The amount she will have at the end of 5 weeks = (10 + d)·5

The amount, A, of money Angelica will have at the end of five weeks if d = $25 is given as follows;

A = (10 + 25) × 5 = $175

The amount of money Angelica will have at the end of five weeks if d = $25 is $175.

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3 years ago

Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad

laila [671]

Answer:

$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$