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vaieri [72.5K]
3 years ago
5

6x-2x+8y-6y (algebra answr very urgent

Mathematics
2 answers:
Lesechka [4]3 years ago
8 0

Answer:

4x+2y

Step-by-step explanation:

6x-2x+8y-6y

4x+2y

Masteriza [31]3 years ago
3 0
Answer: 4x + 2y
Combine like terms
6x - 2x = 4x
8y - 6y = 2y
4x + 2y
I hope this helps :)
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No links!! <br> i’m stuck can someone please help me asap!
Vinvika [58]

Answer:

7,3,5,1???

Step-by-step explanation:

3 0
3 years ago
Which equation requires the division property of equality to be solved?
Ymorist [56]

Answer:

A. 201.6 = 11.2f

Step-by-step explanation:

we solve for each unknown to verify which equality will require the division property:

#A. 201.6 = 11.2f

201.6=11.2f\\\\f=\frac{201.6}{11.2}=201.6\div 11.2\\\\=18

Hence, division property used.

#B. 35.4=Z ÷ 3.1

35.4=Z\div 3.1\\\\35.4=\frac{Z}{3.1}\\\\Z=35.4\times 3.1\\\\=109.74

Hence, multiplication property used.

#C. t/3.2=15.1

\frac{t}{3.2}=15.1\\\\t=15.1\times 3.2\\\\=48.32

Hence, multiplication property used.

#D. 201.6 = 11.2+c

201.6=11.2+c\\\\201.6-11.2=c\\\\c=190.4

Hence, subtractionproperty used.

5 0
3 years ago
Read 2 more answers
What's the answer for <br>3.4a=57.8
crimeas [40]
In the equation 3.4a = 57.8, a is equal to: 17.
7 0
3 years ago
sfiso is not attending school on Saturday 1/3 of the day on sleep, 1/8 of his time on homework, 2/6 of the day playing and 5 hou
Natali [406]

Answer:

1/3+1/8+2/6=19/24-5=1/24

8 0
2 years ago
Suppose you know the length of a confidence interval of a population mean is 8.4 and the sample mean (x bar) is 10. Find the ​ma
SOVA2 [1]

Answer:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=10 represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Solution to the problem

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

4 0
3 years ago
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