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Tasya [4]
3 years ago
11

Fill in the blank:

Mathematics
1 answer:
professor190 [17]3 years ago
3 0

Answer:

1. 4

2. -7

3. 3

4. -7.5

Step-by-step explanation:

They are opposites on a number line thereforeit would be your answer. Hope this helps you :)

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What is the ratio of the number of days in the week that begin with the letter "T" to the number of days in the week that do not
ioda

Answer:

2:5

Step-by-step explanation:

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A total of 507
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Answer:

507-57 = 450 adult tickets

hope this helps :) plz brainliest if helps

Step-by-step explanation:

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3 years ago
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Find the equation of the line (0,-5) and (5,0)
liraira [26]
I think it is 4.5 but I might be wrong
7 0
3 years ago
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Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
Which expression is equivalent to
ozzi
The answer for the question shown above is the first option: x^2(x^2)^1/4
 When you simplify the expression, you obtain the equivalent expression:

 (x^10)^1/4
 [(x^8)(x2)]^1/4
 x^2(x^2)^1/4

 Therefore, the asnwer is the option mentioned before.
5 0
4 years ago
Read 2 more answers
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