Prime factorization involves rewriting numbers as products
The HCF and the LCM of 1848, 132 and 462 are 66 and 1848 respectively
<h3>How to determine the HCF</h3>
The numbers are given as: 1848, 132 and 462
Using prime factorization, the numbers can be rewritten as:
The HCF is the product of the highest factors
So, the HCF is:
<h3>How to determine the LCM</h3>
In (a), we have:
So, the LCM is:
Hence, the HCF and the LCM of 1848, 132 and 462 are 66 and 1848 respectively
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3
- x 6 = 4
4
Mary has 6 cakes, she gives 3/4 of the cakes away. How many cakes does Mary have?
Answer:
Step-by-step explanation:
25+105+x=180 degree(being sum of the interior angles of a triangle)
130+x=180
x=180-130
x=50 degree
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
(6/13)/(6/12)= (6/13)*(12/6)= 12/13
This rule for division applies to all fraction divisions
