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3 years ago

Which Subset of the real numbers contain 3/4

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

7 0

Answer: Rational numbers

Explanation:

Any rational number is of the form p/q

p and q are integers where q is nonzero

In the case of 3/4, p = 3 and q = 4.

The set of integers is {..., -3, -2, -1, 0, 1, 2, 3, ... } consisting of positive and negative whole numbers, with 0 included as well.

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BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers

Joshua uses the escalator in the shopping mall to get to the ground floor from the underground garage located at (12,-5). Which

alina1380 [7]

Answer:

(4,5)

Step-by-step explanation:

Initial location of Joshua in the shopping mall is expressed according to the coordinate (12, -5)

If he undergoes a translation of 8 steps to the left and 10 steps upwards, this means that he moves 8 steps towards the negative x axis and 10 steps towards the positive y axis. The new coordinate will be gotten by adding the translation (-8, 10) to the initial coordinate as shown

New position = (12, -5) + (-8,10)

New position = (12-8, -5+10)

New position = (4, 5)

Hence the coordinates that corresponds to the location of the ground floor when undergoing a translation of 8 steps to the left and 10 steps upwards will be (4,5)

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3 years ago

What is the answer to this quation

svetlana [45]

Answer:

Step-by-step explanation:

g(t)=t^2 - t

f(x) = (1 + x)

g(f(x)) = f(x)^2 - f(x)

g(f(x)) = (x + 1)^2 - x - 1

g(f(0)) = (0 +1)^2 - x - 1

g(f(0)) = 1 - 1 - 1 = -1

================================

f(x) = 1 + x

f(g(t)) = 1 + g(t)

f(g(t)) = 1 + t^2 - t

f(g(0)) = 1 + 0 - 0

f(g(0)) = 1

The answer I'm getting is 0.

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4 years ago

Whats a fraction thats equivalent to 3/12

Ad libitum [116K]

Answer:

1/4

Step-by-step explanation:

Yes

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3 years ago

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Vesnalui [34]

Answer:

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Step-by-step explanation:

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