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Andreyy89
3 years ago
13

EAB and DCB are two right triangles. The figure has BED≅ BDE. Point B is the midpoint of segment AC. Prove: EAB≅ DCB

Mathematics
1 answer:
aleksklad [387]3 years ago
5 0
See the attached picture. 

<span>you are given that ABCE is an isosceles trapezoid. </span>

<span>you are given that AB is parallel to EC. </span>

<span>this means that AE is congruent to BC. </span>

<span>you are given that AE and AD are congruent. </span>

<span>triangle EAD is an isosceles triangle because AE and AD are congruent. </span>

<span>this means that angle 1 is equal to angle 3. </span>

<span>since angle 1 is equal to angle 2 and angle 3 is equal to angle 1, then angle 3 is also equal to angle 2. </span>

<span>this means that AD and BC are parellel because their corresponding angles (angles 3 and 2) are equal. </span>

<span>since AB is parallel to EC and DC is part of the same line, than AB is parallel to DC. </span>

<span>you have AB parallel to DC and AD parallel to BC. </span>

<span>if opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. </span>

<span>that might be able to do it,depending on whether all these statements are acceptable without proof. </span>

<span>they are either postulates or theorems that have been previously proven. </span>

<span>if not, then you need to go a little deeper and prove some of the statements that you used.. </span>

here's my diagram. 

 

<span>this is not a formal proof, but should give you some ideas about how to proceed. </span>

<span>you can also prove that angle 4 is equal to angle 2 because they are alternate interior angles of parallel lines. </span>

<span>you can also prove that angle 6 is equal to angle 5 because they are alternate interior angles of parallel lines. </span>
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