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Kruka [31]
3 years ago
5

Find another way to name the plane M shown in the figure

Mathematics
2 answers:
ivolga24 [154]3 years ago
6 0

Answer:

Plane RTS

Step-by-step explanation:

goldfiish [28.3K]3 years ago
3 0

Answer: Choice D) Plane PQY

==========================================================

Explanation:

By definition, a plane is formed by 3 non-collinear points. The three points cannot all be on the same line. If you had 3 points on the same line, then infinitely many planes are possible. Imagine the plane spins around the line as a sort of fan blade.

Choice A can be ruled out because points R, T, and S are all on the same line. They are collinear points. Using these three points is not enough to properly identity/label this plane, since infinitely many other planes could result.

Choices B and C can also be ruled out for similar reasons.

Choice D is correct because points P, Q, and Y are all in plane M, and also because they are not all on the same line.

Side note: another way to phrase "a plane is formed by 3 non-collinear points" is to say "a plane is formed by 3 points that form a triangle".

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Which of the following is most likely to bra relative maximum for this graph?
Inessa [10]

Answer:

(-1,8)

Step-by-step explanation:

Look at the top point of the parabola type thing. I know that it's not a parabola, but IDRK how else to describe it. If you see the top point at one of the answers, it is most likely correct.

4 0
2 years ago
13/17% of a quantity is equal to what fraction of the quality
Nookie1986 [14]

Answer:

13/1700

Step-by-step explanation:

so you do 13/17 x 1/100 which is 13/1700 please mark brainliest

8 0
3 years ago
Read 2 more answers
In a simple regression analysis for a given data set, if the null hypothesis β = 0 is rejected, then the null hypothesis ρ = 0 i
kati45 [8]

Answer:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degrees of freedom

And the statistic to check the significance of a coeffcient in a regression is given by:

t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}

For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:

Always

Step-by-step explanation:

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degrees of freedom

And the statistic to check the significance of a coeffcient in a regression is given by:

t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}

For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:

Always

4 0
2 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
2 years ago
7x-18 is less than or equal to 32
gavmur [86]
We have
7x - 18 \leqslant 32 \\ 7x - 18 + 18 \leqslant 32 + 18 \\ 7x \leqslant 50 \\ x \leqslant 50  \div 7 \\
we have x is less than or equal 50/7
8 0
3 years ago
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