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timofeeve [1]
3 years ago
5

Solve the following quadratic for the values x

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

x² + 6x - 27 = 0

x² + 9x - 3x - 27 = 0

x ( x + 9 ) - 3 ( x + 9 ) = 0

( x + 9 ) ( x - 3 ) = 0

Thus ,

x = -9 or x = 3

I hope it helps you

#Indian : )

mestny [16]3 years ago
4 0

{x}^{2}  + 6x - 27 = 0 \\ D= {6}^{2}  - 4 \times ( - 27) = 36 + 108 = 144 =  {12}^{2}  \\ x_1= \dfrac{ - 6 + 12}{2}  = 3 \\ x_2= \dfrac{ - 6 - 12}{2}  =  - 9

Answer: x=3; x=-9

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The 1st term in a geometric series is 5 and the common ratio is 2. Find the sum of the 1st 10 terms in the series.
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3 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

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3 0
3 years ago
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lesya692 [45]
Download photo math for equations like this, it will also give you it step by step :)
4 0
2 years ago
Someone please help, having trouble with this
Dennis_Churaev [7]

Answer:

C

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B and D are completely inapplicable

pls brainliest

8 0
3 years ago
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