I will assume that you meant:
(x+4)/(-3x^2+12x+36) factor the denominator...
(x+4)/(-3(x^2-4x-12))
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=-12 and j+k=b=-4 so j and k must be 2 and -6 and the factors are then:
(x+2)(x-6) so we are now left with:
(x+4)/(-3(x+2)(x-6))
The only restriction on this function is that division by zero is undefined, so x cannot equal -2 or 6
Here’s the answer. See pictures.
Answer:
So the vaule of y is 7, 10 & 13
Step-by-step explanation:
Given that y = 3x+1 . So we can just substitute x-value into the equation :
Let x=2,
y = 3(2)+1
= 7
Let x=3,
y = 3(3)+1
= 10
Let x=4,
y = 3(4)+1
= 13
Answer:
B
Step-by-step explanation:
x is the value of x which you input into the function and f(x) is the actual function and therefore the output. so when x=3, f(x)= -2. f(3)=-2
5 and 7… 5x7=35
you’re welcome
