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lina2011 [118]
3 years ago
8

Who this also ?? Help please :)

Mathematics
2 answers:
ryzh [129]3 years ago
4 0

Answer:

Step-by-step explanation:

b

b

lol

hope this helps <3

STALIN [3.7K]3 years ago
3 0

Answer:

in y=mx + b, b is the y intercept. Sp answer choice d.

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Could you please help me if you know how to do this
ArbitrLikvidat [17]

Answer:

In the first one, 4 is multiplied by c. In the second one, 1/4 is multiplied by c.

Step-by-step explanation:

8 0
3 years ago
Help me with this math please
Bas_tet [7]
It means that The bicyclist rides 64 miles in 4 hours!! :)
5 0
3 years ago
Read 2 more answers
Felix’s feed mill sells chicken feed for $8.00 per bag. this price is no longer high enough to create a profit. felix decides to
nydimaria [60]
First, is to raise the price to earn profit. Second, is to maintain the price to maintain the number of buyers. Third, is  to maintain the price but to lessen the chicken feed inside a bag. Fourth, to tell the customers first that you will raise the price of your product. 
3 0
3 years ago
Find the GCF of 14a5 and 22a3
miskamm [114]
I am assuming that you mean 14 a^{5} and 22 a^{3}

Now, let's look for common factors.  The first one is a^{3}  After we take that out, we are left with 14 and 22.  We can take a 2 out of both of these, so the greatest common factors is 2a^{3}
4 0
3 years ago
Find all intervals on which the graph of f(x)=(x-1)/(x+3) is concave upward
Yuliya22 [10]
To find concavity we need to find the second derivative.
Use quotient rule to find f'(x)=4/(x+3)^2
Then use chain rule to find f''(x)=-8/(x+3)^3
To find potential inflection points, we need to find all x values where the second derivative is equal to 0 or is undefined.

Set the numerator and denominator equal to 0 and solve.

(x+3)^3=0
x+3=0
x= -3

Now plug a value less than -3 and greater than -3 into the second derivative to find where the concavity is upward (positive number).

Since f''(-4) is positive, that means that f(x) is concave up on the interval (-infinity, -3).




4 0
4 years ago
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