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Andreyy89
3 years ago
14

What is the slope of the line that passes through the points (8,8) and

Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

\frac{5}{6}

Step-by-step explanation:

Alchen [17]3 years ago
6 0

Answer:

-5/6

Step-by-step explanation:

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- 6x +15 <br>Can anyone please show me the steps of solving this equation​
Vesna [10]

Answer:

-6x + 15 = - 69 which x = 14

Step-by-step explanation:

You cannot solve this equation. There is no equal sign anywhere. Either you mean

-6x = 15 in which case the answer is

-6x/-6 = 15/-6

x = - 2 1/2 or x= - 2.5

or you mean that you use the distributive property

- 3(2x + 5)

You may have left something out of this.

-6x + 15 = -  69

You can do it now that you have the complete equation. But you need the entire equation before you can answer the question.

Subtract - 15 from both sides.

-6x + 15 - 15 = -69 - 15

-6x = - 84

Divide by - 6

-6x/-6 = - 84/-6

x = 14

But what you want is

-6x + 15

-6*14 + 15

-84 + 15

-69

-6x + 15 = - 69

when x = 14 which is usually what you are asked.

5 0
3 years ago
Write 7.104 as a fraction or mixed number
Amiraneli [1.4K]
7 with 13 over 125 this is the mixed number form.
8 0
3 years ago
Read 2 more answers
Clarissa got a part time job during the first week she earned $439.50. During the second and third week she worked a total of 62
iren2701 [21]

Answer:

$2063.44

Step-by-step explanation:

1st week = $439.50

2nd and 3rd week = 62 hours and each hour = $22.79

Total amount earned in 2nd and 3rd week = 62 * 22.79 = $1412.98

4th week = 48% of what she earned in her first week = 48% of $439.50

4th week = (48 / 100) * 439.50 = $210.96

Total amount she earned = 1st week + 2nd & 3rd week + 4th week

Total amount = $439.50 + $1412.98 + $210.96

Total amount = $2063.44

She earned a total of $2063.44

6 0
4 years ago
Find the distance between the points (4,-2) and (0,10)
vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: \sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}} We can now put in values and solve.

\sqrt{(4-0)^{2} + (-2-10)^{2}}  

\sqrt{16 + 144}

\sqrt{160} 

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28
Nataliya [291]
Assuming you mean

5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t

This ODE is linear in y, and you can already contract the left hand side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t

Integrating both sides with respect to t yields

5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt
5y\sin t=\dfrac13\sin^3t+C
y=\dfrac1{15}\sin^2t+C\csc t

Given that y\left(\dfrac\pi2\right)=9, we have

9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2
9=\dfrac1{15}+C
C=\dfrac{134}{15}

so that the particular solution over the interval is

y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t
6 0
3 years ago
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