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Tanzania [10]
3 years ago
9

Which of the following values are in the range of the function graphed below? check all that apply

Mathematics
2 answers:
vodomira [7]3 years ago
5 0

Answer:

Option D. 1

Option E. 1/2

Step-by-step explanation:

we know that

Looking at the graph

The domain is the interval ----> [-1,1]

-1\leq x\leq 1

The domain is all real numbers greater than or equal to -1 and less than or equal to 1

The range is the interval ----> [0,1]

0\leq y\leq 1

The range is all real numbers greater than or equal to 0 and less than or equal to 1

therefore

The values that are in the range are

1 and 1/2

olasank [31]3 years ago
5 0

Answer:

D.1

E.\frac{1}{2}

Step-by-step explanation:

We have to find the values lie in the range of function in given graph.

Let f(x) be given function

Domain takes along x- axis and range takes along y- axis.

From given graph , we can see that

Domain of function =[-1,1]

It means

-1\leq x\leq 1

Range of function:[0,1]

It means

0\leq y \leq 1

The value of range of given function  from 0 to 1.

Hence, option D and E are correct.

D.1

E.\frac{1}{2}

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For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?​
konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

After solving we get value of y=-1

Now putting in eq(1) to get value of x

x+2y=0\\x+2(-1)=0\\x-2=0\\x=2

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3

So, After solve the equations we get value of k=3

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3 years ago
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