Answer:
Because of the minus sign
2 becomes - 2
The answer is -2
Multiply a and 7
Multiply a and 1
The a just gets copied along.
The answer is a
a
7*a evaluates to 7a
Multiply b and 4
Multiply b and 1
The b just gets copied along.
The answer is b
b
4*b evaluates to 4b
7*a+4*b evaluates to 7a+4b
Multiply -2 by 7a+4b
we multiply -2 by each term in 7a+4b term by term.
This is the distributive property of multiplication.
Multiply -2 and 7a
Multiply 1 and a
The a just gets copied along.
a
-2 × 7a = -14a
Multiply -2 and 4b
Multiply 1 and b
The b just gets copied along.
b
-2 × 4b = -8b
-2*(7*a+4*b) evaluates to -14a-8b
Multiply c and 6
Multiply c and 1
The c just gets copied along.
The answer is c
c
6*c evaluates to 6c
The answer is -14a-8b-6c
-2*(7*a+4*b)-6*c evaluates to -14a-8b-6c
The final answer is
-14a-8b-6c
Step-by-step explanation:
Please mark brainliest and have a great day!
Simplifying is basically 1 + 1, so the answer is 2, or 8/4 whichever you prefer.
It can also be 4/2, or 2/1...
Answer:
The current temperature on the X scale is 1150 °X.
Step-by-step explanation:
Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:
![r = \frac{\Delta T_{X}}{\Delta T_{Y}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%5CDelta%20T_%7BX%7D%7D%7B%5CDelta%20T_%7BY%7D%7D)
![r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B325%5C%2C%5E%7B%5Ccirc%7DX-%28-115%5C%2C%5E%7B%5Ccirc%7DX%29%7D%7B-25%5C%2C%5E%7B%5Ccirc%7DY%20-%20%28-65.00%5C%2C%5E%7B%5Ccirc%7DY%29%7D)
![r = 11\,\frac{^{\circ}X}{^{\circ}Y}](https://tex.z-dn.net/?f=r%20%3D%2011%5C%2C%5Cfrac%7B%5E%7B%5Ccirc%7DX%7D%7B%5E%7B%5Ccirc%7DY%7D)
The difference between current temperature in Y linear scale with respect to freezing point is:
![\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)](https://tex.z-dn.net/?f=%5CDelta%20T_%7BY%7D%20%3D%2050%5C%2C%5E%7B%5Ccirc%7DY%20-%20%28-65%5C%2C%5E%7B%5Ccirc%7DY%29)
![\Delta T_{Y} = 115\,^{\circ}Y](https://tex.z-dn.net/?f=%5CDelta%20T_%7BY%7D%20%3D%20115%5C%2C%5E%7B%5Ccirc%7DY)
The change in X linear scale is:
![\Delta T_{X} = r\cdot \Delta T_{Y}](https://tex.z-dn.net/?f=%5CDelta%20T_%7BX%7D%20%3D%20r%5Ccdot%20%5CDelta%20T_%7BY%7D)
![\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)](https://tex.z-dn.net/?f=%5CDelta%20T_%7BX%7D%20%3D%20%5Cleft%2811%5C%2C%5Cfrac%7B%5E%7B%5Ccirc%7DX%7D%7B%5E%7B%5Ccirc%7DY%7D%20%5Cright%29%5Ccdot%20%28115%5C%2C%5E%7B%5Ccirc%7DY%29)
![\Delta T_{X} = 1265\,^{\circ}X](https://tex.z-dn.net/?f=%5CDelta%20T_%7BX%7D%20%3D%201265%5C%2C%5E%7B%5Ccirc%7DX)
Lastly, the current temperature on the X scale is:
![T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X](https://tex.z-dn.net/?f=T_%7BX%7D%20%3D%20-115%5C%2C%5E%7B%5Ccirc%7DX%20%2B%201265%5C%2C%5E%7B%5Ccirc%7DX)
![T_{X} = 1150\,^{\circ}X](https://tex.z-dn.net/?f=T_%7BX%7D%20%3D%201150%5C%2C%5E%7B%5Ccirc%7DX)
The current temperature on the X scale is 1150 °X.