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2 years ago

11

Steve Wilson is given a $200 budget to prepare a five-course meal. If the main course costs $80 to prepare, what fraction of the

budget was used for the main course?

1 answer:

posledela2 years ago

5 0

I think the answer is 2/5.

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You are planning to build a new home with approximately 2,000-2,500 gross square feet of living space on one floor. In addition,

Sphinxa [80]

Answer:

The unanimous Declaration of the thirteen united States of America, When in the Course of human events, it becomes necessary for one people to dissolve the political bands which have connected them with another, and to assume among the powers of the earth, the separate and equal station to which the Laws of Nature

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2 years ago

The process of when a product is recycled back into almost the same product, is called?

Setler [38]

When a product is recycled back into almost the same product it's called 'reuse.' There are three R's - reduce, reuse, and recycle. When a product, such as paper, is recycled and made again into paper or a paper product, this is called reuse.

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3 years ago

If actual sales totaled $500,000 for the current year (40,000 units at $12.50 each) and planned sales were $495,000 (45,000 unit

irina [24]

Answer: <u>The answer is A. $60,000 increase.</u>

<u />

Explanation: 1: The actual units sold multiplied by the budgeted sale price is equal to a total of $440000 (40000 x 11 = $ 440000)

2: The actual units sold multiplied by the actual sale price is equal to $500000 (40,000 x 12.5 = $ 500,000)

3:<u> $500000 - $440000 = </u><u>$60000</u><u> increase by the unit price factor.</u>

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4 0

2 years ago

You plan on saving for a large home improvement project using the following cash flows: $50,000 today, $25,000 next year, and $1

lesya692 [45]

Answer:

Total= $98,000

Explanation:

Giving the following information:

You plan on saving for a large home improvement project using the following cash flows: $50,000 today, $25,000 next year, and $10,000 the following year. The account earns a 10% return per year.

We need to use the following formula:

FV= PV*(1+i)^n

FV= 50,000*1.10^2= 60,500

FV= 25,000*1.1= 27,500

FV= 10,000

Total= $98,000

8 0

3 years ago

Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,

wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time = mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be $I_i$ :

$I_i = \dfrac{R^2}{\mu (\mu-R)}$

$I_i = \dfrac{2.1^2}{5 (5-2.1)}$

$I_i = \dfrac{4.41}{5 (2.9)}$

$I_i = \dfrac{4.41}{14.5}$

$\mathbf{I_i = 0.30}$

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

$\delta = \dfrac{R}{\mu}$

$\delta = \dfrac{2.1}{5}$

${\delta = 0.42}$

$\mathbf{\delta = 42}$

(c) The amount of time during an eight-hour day that the repairman is not out on a call is calculated as :

Percentage of Idle time = 1 - $\delta$

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58 × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0

3 years ago