1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WINSTONCH [101]
3 years ago
13

136/50 as a percentage?

Mathematics
2 answers:
aleksandrvk [35]3 years ago
4 0

Answer: 272%

Step-by-step explanation: To write 136/50 as a percent have to remember that 1 equal 100% and that what you need to do is just to multiply the number by 100 and add at the end symbol % .

136/50 * 100 = 2.72 * 100 = 272%

And finally we have:

136/50 as a percent equals 272%

pickupchik [31]3 years ago
3 0
272%

136/50=272/100

I have a goal of 20 brainliest please help if you can :D
You might be interested in
A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
Aneli [31]

a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
4 years ago
Pls someone help me im in a test and im stresssssing??
Dennis_Churaev [7]
Positive 5/8 hope this helps :) uno reverse btw lol
3 0
3 years ago
In the supply-and-demand schedule shown above, the equilibrium price for portable music players is _____.
ad-work [718]
$150 because the supply number is equivalent to the demand number
6 0
3 years ago
Read 2 more answers
Graph the function. ( Look at the picture for the problem and graph. Need help and please only answer if you know the right answ
aliya0001 [1]

Answer:

there is a website called desmos and you can type all of that in and it can graph it, hope that helps(: and its free

5 0
3 years ago
Triangle ABC is transformed to triangle A′B′C′, as shown below:
Montano1993 [528]

Answer:

C. m<CAB = m<C'A'B'

Step-by-step explanation:

Triangle ABC looks like it was only reflected over the line y = 0. If the triangle was only reflected then the triangles should be congruent to each other.

3 0
3 years ago
Other questions:
  • PLEASE HELP WITH ALGEBRA
    12·2 answers
  • Two squares have perimeters of 25 yards and 100 yards respectively. How many times greater is the perimeter of the larger square
    8·2 answers
  • Please simplify 3/5(25n-10y+5n)<br> please show work
    12·1 answer
  • Consider the triangle.
    6·2 answers
  • Which shapes will have an area of 24 m2, CHOOSE ALL THAT APPLY (A) a triangle with a base of 6m and height of 4m (B) a parallelo
    14·1 answer
  • Help^0^
    11·1 answer
  • If a sample mean is 37,which of the following is most likely the range of possible values that best describes an estimate for th
    15·2 answers
  • Explain why that price seems to be a linear function of the number of boxes ordered?<br> Heeeeeelp
    7·1 answer
  • Y is directly proportional to x. when y=30, x=6. A) work out an equation connecting y and x. B) work out what the value of y whe
    13·1 answer
  • The difference of a number k and 8 .1 is greater than 24.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!