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2 years ago

Solve for x: ( x - 2 ) ( x + 3 ) ( 2x - 7 ) = 0

Mathematics

1 answer:

Alika [10]2 years ago

6 0

Answer:

x=2, x=-3, or x=3.5

Step-by-step explanation:

Make them all in 3 equations equal to 0. The number of brackets, the number of equations.

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Can you please help you have to type in a number her is the screenshot

lyudmila [28]

Answer:

Step-by-step explanation:

Rate = (20½ pounds)/(4 hours) = (5⅛ pounds)/hour

9 hours × (5⅛ pounds)/hour = 46⅛ pounds

4 0

3 years ago

The question is.......

Hunter-Best [27]

multiply the 2 numbers together than divide by 2

7 1/2 = 15/2

12 2/3 = 38/3

15/2 * 38/3 = 570/6 =95

95/2=47.5 square feet

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3 years ago

Read 2 more answers

Suppose you are fencing a rectangular dog pen. The pen is to be 15 feet long and 7 feet wide. How much fencing would you need?

Readme [11.4K]

Answer:

44 feet

Step-by-step explanation:

15 + 15 + 7 + 7 = 44

We can take all 4 sides and add them together to find the perimeter (aka how much fencing you need)

hope this helps :)

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3 years ago

Read 2 more answers

Honey and Money are twin brothers. Mother wants to equally divide a rectangular shaped cake of 5cm wide and 6cm long. Find the l

tatuchka [14]

Answer:

Length of rectangular cake = 5 cm

Breadth of rectangular cake = 6 cm

Area of rectangle = 5 cm × 6 cm =30 cm²

If cake is equally distributed between Honey and Money, then areas of two parts should be equal.

So, Amount of cake that Honey and money got $\frac{30}{2}=15$

Share of each (Honey and Money)=15 cm²

So, if the third cake if it was cut diagonally ,the cake must have some height.

Let the height of cake be H.

So, Height of third cake $=\sqrt{L^2+B^2+H^2}\\\\=\sqrt{5^2+6^2+H^2}\\\\=\sqrt{61+H^2}$

If , H=0 that is height is negligible having 0 thickness,

Then the Length of third cake, which is divided into two parts=√61=7.81 cm

5 0

3 years ago

For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =

enyata [817]

Given that <span>For a certain model of car the distance $d$ required to stop the vehicle if it is traveling at $v$ mi/h is given by the formula $d=v+\frac{v^2}{20}, where [tex]d$ is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

$v+ \frac{v^2}{20} \leq75 \\ \\ 20v+v^2\leq1,500 \\ \\ v^2+20v+100\leq1,500+100 \\ \\ (v+10)^2\leq1,600 \\ \\ |v+10|\leq\sqrt{1,600} \\ \\ -40\leq v+10\leq40 \\ \\ -40-10\leqv\leq v\leq40-10 \\ \\ -50\leq v\leq30$

Therefore, the range of speed she can travel is $v\leq30\ mi/hr$
</span>

8 0

3 years ago