Plug in 10 for x in h(x) then simplify
h(10)=2(10)-8
h(10)=20-8
h(10)=12
h(10) is 12 so put 12 in for g(x)
g(h(10))=12-4
g(h(10))=8
Here’s everything together
g(h(10))=(2(10)-8)-4
=(20-8)-4
=(12)-4
=8
This is what I’ve always done. I can’t really tell what your answers are so sorry if this isn’t right at all.
pi·(7.2/2)^2·x = 2·pi·(7.2/2)^2 + 2·pi·(7.2/2)·x
x = 4.5 = 4 1/2
O = V = 1458/25·pi = 58.32·pi
Yes, all of the rhombuses have 2 pairs of parallel side.