For this case we must solve the expression given for the variable "m":

We add 5 to both sides of the inequality:

Multiplying by 2 to both of the inequality:

So, finally we have:

The solution is given by all values of m less than 4.
Answer:

Answer:
<h2>
-3
</h2>
Step-by-step explanation:
chage the proper fraction to improper and then multiply
Did you ever find the answer?
Answer:
atq= let no.be x and y
x= 4y-3.......(1)
x-2y=7....(2)
subtracting both eqn
x-x+2y=4y-3-7
2y=4y-10
-2y= -10
y=5 ........second no.
first no...x=7+2y=7+10=17.......first no....
Answer:

Step-by-step explanation:
The mean is the sum of the allowances divided by the number of students.
