Answer:
3.5
Step-by-step explanation:
just trust me on this one i dont really know how to show my work
<span><span>x3</span>+3<span>x2</span>−9x−27=<span>(x−3)</span><span>(x+3)</span><span>(x+3<span>)</span></span></span>
8.333333 reoccurring. 1 divided into 6 is 1.666667. Multiply by the remaining amount, 5? Idk
Okay !! what’s the question ?
Q1. The limit from the right is -4. (The limit from the left, and the value of f(3) are different, but that doesn't matter for the question asked. Taken together, they mean that the limit as x approaches 3 does not exist. But that is not the question asked.)
Q2. f(x) = 4/x.
f'(x) = -4/x^2, so f'(2) = -4/2^2 = -1.
Q3. Since the denominator is zero at x=7, the only answer choice that makes any sense is the first one:
-∞; x = 7
It also happens to be the right one.