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atroni [7]
3 years ago
8

I need help pls it’s timedd!!!!

Mathematics
2 answers:
9966 [12]3 years ago
7 0

in BCD triangle :

DC^2 = BC^2 + BD^2

13^2 = 12^2 + BD^2

169 = 144 + BD^2

BD^2 = 169 - 144

BD^2 = 25

BD = 5

_______________________

In the other hand we have :

BD^2 = AB × BC

5^2 = AB × 12

AB = 25/12

________________________

Also we have :

AD^2 = AB × AC

AD^2 = 25/12 × ( 25/12 + 12 )

AD^2 = 25/12 × ( 25/12 + 144/12 )

AD^2 = 25/12 × 169/12

AD^2 = 25 × 169 / 12 × 12

AD^2 = 5 × 5 × 13 × 13 / 12 × 12

AD = 5 × 13 / 12

AD = 65 / 12

AD = 5.42

Thus the correct answer is option C

sashaice [31]3 years ago
6 0

Answer:

5.

Step-by-step explanation:

If you were to rotate the triangle, you can apply Pythagoras Theorem.

Therefore,

a^2 = 12^2 - 13^2 (Note: a^2 = a squared)

a^2 = 144 - 169

a^2 = -25.

a     = 5.

Not sure why its negative though im pretty sure its the right answer.

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angle8 = angle5 (vertically opposite angles)

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Therefore, angle8 is basically the same as angles 1 and 4

Thus,

127+127=254

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Step-by-step explanation:

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A psychology professor assigns letter grades on a test according to the following scheme. A: Top 7% of scores B: Scores below th
NISA [10]

Answer:

The minimum score required for an A grade is 89.8.

Step-by-step explanation:

We are given that a psychology professor assigns letter grades on a test according to the following scheme. A : Top 7% of scores. B : Scores below the top 7% and above the bottom 64%. C : Scores below the top 36% and above the bottom 25%. D : Scores below the top 75% and above the bottom 6%. F : Bottom 6% of scores.

Scores on the test are normally distributed with a mean of 78.4 and a standard deviation of 7.6.

<u><em>Let X = Scores on the test</em></u>

SO, X ~ Normal(\mu=78.4,\sigma^{2} =7.6^{2})

The z-score probability distribution for normal distribution is given by;

                              Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean time = 78.4

            \sigma = standard deviation = 7.6

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, the minimum score required for an A grade so that it represents Top 7% of scores is given by;

      P(X \geq x) = 0.07   {where x is the required minimum score

      P( \frac{X-\mu}{\sigma} \geq \frac{x-78.4}{7.6} ) = 0.07

       P(Z \geq \frac{x-78.4}{7.6} ) = 0.07

<em>So, the critical value of x in the z table which represents the top 7% of the area is given as 1.4996, that is;</em>

                        \frac{x-78.4}{7.6} =1.4996

                        {x-78.4}{} =1.4996\times 7.6

                        x  = 78.4 + 11.39696 = <u>89.8 or 90</u>

Hence, the minimum score required for an A grade is 89.8.

8 0
3 years ago
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