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3 years ago

PLS HELP AND EXPLAIN THE ANSWER

Mathematics

2 answers:

Greeley [361]3 years ago

8 0

The answer above is wrong, it is A

Naddika [18.5K]3 years ago

7 0

Answer:

the answer is d!! I hope it helped please lmk if not

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I will give brainliest

grandymaker [24]

Jsjs:))))))))))otay /:

4 0

3 years ago

Order the fraction to least to greatest 7\9 13\18 5\6 2\3

Olegator [25]

First, you need to have a common denominator for all of them, in this case, they can all go in 18 so that will be the common denominator.

$\frac{7}{9} x \frac{2}{2} = \frac{14}{18}$
$\frac{5}{6} x \frac{3}{3} = \frac{15}{18}$
$\frac{2}{3} x \frac{6}{6} = \frac{12}{18}$
$\frac{13}{18}$

Now you can tell which ones are the biggest or smallest. So from least to greatest you would have this.

$\frac{2}{3} , \frac{13}{18} , \frac{7}{9} , \frac{5}{6}$

7 0

3 years ago

Jake made punch by combining 2.75 liters of orange juice, 1.25 liters of pineapple juice, and 3.5 liters of soda. He then poured

cluponka [151]

Answer:

He poured 2.5 liters into each container

Step-by-step explanation:

Add 2.75, 1.25, and 3.5 together to get 7.5. Divide 7.5 by 3 and you get 2.5 liters per container.

7 0

3 years ago

Question. 1 :

vovikov84 [41]

<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0

3 years ago

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

katrin2010 [14]

Greetings and Happy Holidays!

<span>1) Perpendicular to </span> $-x+5y=14$
In order for lines to be perpendicular, their slopes must be negative reciprocals.
Example of slopes with negative reciprocals: 5 and $\frac{-1}{5}$

First, rearrange the equation into slope y-intercept form:
$-x+5y=14$

$5y=x+14$

$\frac{5y}{5}=\frac{x+14}{5}$

$y=\frac{1}{5}x+\frac{14}{5}$

The slope of the equation is: \frac{1}{5}

The negative reciprocal formula: $(m_{1})(m_{2})=-1$

Solve for the negative reciprocal:
$\frac{1}{5}m_{2}=-1$

Divide both sides by $\frac{1}{5}$
$\frac{\frac{1}{5}m_{2} }{ \frac{1}{5}} = \frac{-1}{ \frac{1}{5}}$

$m_{2}=(-1)(\frac{5}{1})$

$m_{2}=(\frac{-5}{1})$

$m_{2}=-5$

The slope of the new line is: -5

2) Passes through (-5,-2)

Create an equation with the slope discovered in slope y-intercept form.
$y=-5x+b$

Input the point the line passes through.
$(-2)=-5(-5)+b$

Solve for b (the y-intercept).
$-2=-5(-5)+b$

Multiply.
$-2=25+b$

Add -25 to both sides.
$(-2)+(-25)=b$

$-27=b$

The y-intercept is equal to -27

The Equation of the line is:
$y=-5x-27$

I hope this helped!
-Benjamin

6 0

4 years ago