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3 years ago

Which ratio is expressed as a unit rate?

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

3 0

Answer:

1.45 per ounce

Step-by-step explanation:

........................

cluponka [151]3 years ago

3 0

Answer:

$1.45: per ounce

Step-by-step explanation:

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Please answer this correctly

Mariana [72]

Answer:

50%

Step-by-step explanation:

The numbers that are 2 and even are 2 and 4.

2 numbers out of 4.

2/4 = 1/2

= 0.5

P(2 or even) = 50%

3 0

2 years ago

Need help ASAP plzzzzzzzzzz

Harlamova29_29 [7]

Answer: I really dont know sorry

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1. If the same number is added to the numerator and subtracted from the denominator of 23/12, the resulting fraction is equivale

ICE Princess25 [194]

Answer:

The number is -2

Step-by-step explanation:

step 1

Find the reciprocal of 2/3

Remember that when multiply a number by its reciprocal, the result is 1

The reciprocal of 2/3 is 3/2

step 2

Let

x-----> the number added to the numerator and denominator

$\frac{23+x}{12-x}=\frac{3}{2}$

Solve for x

$2(23+x)=3(12-x)\\46+2x=36-3x\\2x+3x=36-46\\5x=-10\\x=-2$

step 3

verify

$\frac{23+x}{12-x}$

substitute x=-2

$\frac{23-2}{12+2}$

$\frac{21}{14}$

Simplify

$\frac{3}{2}$ ----> is ok

therefore

The number is -2

8 0

3 years ago

If the radius of circle A is 6 units, calculate the area of the shaded region...

meriva

The formula of an area of a triangle:

$A_{\triangle}=\dfrac{base\cdot height}{2}$

We have:

$\triangle_{FDE}:\ base=height=1\\\triangle_{GDH}:\ base=height=9$

substitute:

$A_{\triangle_{FDE}}=\dfrac{1\cdot1}{2}=0.5\\\\A_{\triangle_{GDH}}=\dfrac{9\cdot9}{2}=40.5$

The formula of an area of a circle:

$A_O=\pi r^2$

We have $r=6$

Substitute:

$A_O=\pi\cdot6^2=36\pi\approx36\cdot3.14=113.04$

The area of the shaded region

$A=A_O-(A_{\triangle_{FDE}}+A_{\triangle_{GDH}})\\\\A=113.04-(0.5+40.5)=113.04-41=72.04\ u^2$

4 0

3 years ago

After heating up in a teapot, a cup of hot water is poured at a temperature of 204°F.

laila [671]

Answer:

Question 1: 0.081 min⁻¹

Question 2: 168ºF

Explanation:

The missing equation is:

$T=T_a+(T_0-T_a)e^{-kt}$

You are given:

Ta = the temperature surrounding the object = 73ºF
T₀ = the initial temperature of the object = 204ºF
t = 2.5 min
T after 2.5 min = 180ºF

Question 1: Find the the value of k.

Substitute the data into the equation and solve for k:

$180\º=73\º+(204\º-73\º)e^{-k\cdot 2.5min}\\ \\ 107\º=131\ºe^{-k\cdot 2.5min}\\\\-k\cdot 2.5min=\ln (107/131)\\\\k=0.081min^{-1}$

Question 2: Find the Fahrenheit temperature of the cup of water, to the nearest degree, after 4 minutes.

Subsititute into the formula and compute:

$T=73\ºF+(204\ºF-73\ºF)e^{-0.081min^{-1}\times 4min}\\ \\ T=73\ºF+(131\ºF)(0.72325024)\\\\T=168\ºF$

4 0

3 years ago