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3 years ago

Find the perimeter of the following square.

Mathematics

1 answer:

myrzilka [38]3 years ago

6 0

Answer:

Step-by-step explanation:

the perimeter of a shape is the sum of it's sides

in a square all sides have the same length

here all sides are 1 inch

so 1+1+1+1 = 4 inches which is D

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a tree increases in diameter each year by .51 cm. If the tree currently has a diameter of 4 inches, how old is the tree

yan [13]

This one is a little tricky because of the conversion but .51 cm converts to roughly .2 inches (actually its .200787 but we will round to .2 for ease of math). 4 in/.2in = 20

Therefore the tree is 20 years old.

Footnote 1cm is equal to .3937 inches so it would be .51cm * .3937in = .200787in

8 0

3 years ago

How many solutions are there to the equation below?

Art [367]

Answer: B.Infinitely many

3 0

3 years ago

AC<br> Round your answer to the nearest hundredth.<br> с<br> B<br> 40°<br> ?<br> 7<br> A

djyliett [7]

theres a calculator yoy can buy, it makes it a lot easier: Texas Instruments TI-84 Plus. its a bit big but it works well.

3 0

3 years ago

Find three consecutive odd integers such that three times the square of the first integer is twelve more than the product of the

7nadin3 [17]

Consecutive odd integers are 2 apart
they are
n,n+2,n+4

3(n²)=12+(n+2)(n+4)
expand
3n²=12+n²+6n+8
3n²=n²+6n+20
minus n² both sides
2n²=6n+20
divide bot sides by 2
n²=3n+10
minus 3n+10 both sides
n²-3n-10=0
factor
(n-5)(n+2)=0
n-5=0
n=5

n+2=0
n=-2
has to be odd, so no

n=5
n+2=7
n+4=9

the integers are 5,7,9

4 0

3 years ago

Choose the equivalent system of linear equations that will produce the same solution as the one given below. (1 point) 4x − 2y =

goldenfox [79]

Answer:

<h3>Option d) 4x + 2y = 10 and 8x = 16 is correct</h3><h3>Therefore 4x + 2y = 10 and 8x = 16 equations have equivalent solution (2,1) is same as the solution of given linear system of equations</h3>

Step-by-step explanation:

Given equations are

$4x-2y=6\hfill (1)$

$2x+y=5\hfill (2)$

<h3>To find the the equivalent system of linear equations that will produce the same solution as for the given equation :</h3>

First find the solution to the given system of equations by elimination method

Multiply the equation (2) into 2 we get

$4x+2y=10\hfill (3)$

Now adding the equations (1) and ( 3) we get

$4x-2y=6$

$4x+2y=10$

_______________

$8x=16$

$x=\frac{16}{8}$

x=2

Therefore the value of x is 2

Substitute the value of x in equation (1) we get

$4(2)-2y=6$

$8-2y=6$

$-2y=6-8$

$-2y=-2$

$y=\frac{-2}{-2}$

y=1

Therefore the value of y is 1

Therefore the solution to the given system of equations is (2,1)

<h3>Now to find the equivalent system of equations have same solution (2,1)</h3>

Verify the equations $4x+2y=10\hfill (4)$ and 8x = 16

From 8x=16

$x=\frac{16}{8}$

x=2

Therefore the value of x is 2

Substitute x=2 in equation (4) we get

4(2)+2y=10

8+2y=10

2y=10-8

2y=2

$y=\frac{2}{2}$

y=1

Therefore the value of y is 1

Therefore the solution is (2,1)

<h3>Therefore option d) 4x + 2y = 10 and 8x = 16 equations have equivalent solution (2,1) is same as the solution of given linear system of equations </h3>

3 0

3 years ago