The account balance after 3 years if the interest is compounded continuously is $5,142.62
<h3>How to find compound interest?</h3>
- Principal, P = $4,700
- Time,t = 3 years
- Interest rate, r = 3%
r = 3/100
r = 0.03 rate per year,
A = Pe^rt
A = 4,700.00(2.71828)^(0.03)(3)
= 12,775.916^0.09
A = $5,142.62
Therefore, the account balance after 3 years if the interest is compounded continuously is $5,142.62
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Answer:
I dont remember how to do this but i wish you luck, try searching on khan academy for how to do this ;)
Step-by-step explanation:
Answer:
y=15
Step-by-step explanation:
y-7=8
Add 7 to each side to cancel out the 7 next to the variable.
You get y=15.
If you divide 13.1 by 2.75 you'll get 4 plus a remainder so we know there are 4 stops at 2.75 intervals. 4*2.75=11. Subtract 11 from 13.1 and the last stretch would be 2.1 miles.
I hope this helped!
<span>It's 1/r!
nCr = n! / r!(n-r)!
nPr = n! / (n-r)!
If you divide the two you'd have:
n! / r! (n-r)! * (n-r)! / n! = 1/r!
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