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irina1246 [14]
3 years ago
8

Help ASAP!!! A researcher tags 48 turtles in 2008. In 2009 she returned and caught 50 turtles, 16 0f which were tagged. In 2010

she returned again and captured 30 turtles, 8 of which were tagged.
A. Use a proportion to estimate the turtle population for 2009
B.Use a proportion to estimate the turtle population for 2010
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Hope it helps

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The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
4 years ago
Help???????????????????????????
7nadin3 [17]
Is the answer 7632? ithink i got it wrong ill check my answer
3 0
4 years ago
What is the solution to this equation?
kirill [66]
The correct answer for the problem above is -23 .

Explanation

1. collect the like terms

2x + x - 11 + 3 - 7x = 15
2x , x , & -7x are like terms
-11 & 3 are like terms

2x + x -7x = -4x
-11 + 3 = -8

2. Move constant to the right-hand side and change its sign .

-4x = 15 + 8
-4x = 23

3. Make the signs on both sides of the equation

-4x = 23 turning into 4x = -23

answer =

4x = -23



7 0
4 years ago
I need help with this if you get it right I will mark you
dlinn [17]

Answer:

18

Step-by-step explanation:

formula= A=v/h

5 0
3 years ago
Read 2 more answers
ALSO NEED HELP ON THIS ONE, ASAP!! (No links, thats all)
meriva

The area of the triangle is 36 in², so she can create only 4 triangles.

6 0
3 years ago
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