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3 years ago

Find the surface area to the nearest whole number.

Mathematics

2 answers:

storchak [24]3 years ago

8 0

The answer it 46 I believe you multiply

Ostrovityanka [42]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find the lateral area of the cylinder.

irina [24]

Answer:

$A=440\ m^2$

Step-by-step explanation:

Given that,

The diameter of the cylinder, d = 10 m

Hight, h = 14 m

Radius, r = d/2 = 5 m

We need to find the lateral area of the cylinder. The formula for the lateral area of the cylinder is given by :

$A=2\pi rh\\\\A=2\times \dfrac{22}{7} \times 5\times 14\\A=440\ m^2$

So, the lateral surface area of the cylinder is equal to $440\ m^2$ .

6 0

3 years ago

What is the slope of the line described by the equation below y-9=-2(x-8)

Nady [450]

-2 the slope is the a value ( in this case 2) in the formula y=ax+b. The value before the x is the slope. So for every x value you increase you go down by 2

4 0

4 years ago

Read 2 more answers

The square pyramid shown below has a slant height of 171717 units and a vertical height of 151515 units.

guajiro [1.7K]

Answer:

The answer is 16.

6 0

3 years ago

what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible

zheka24 [161]

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

Find out more on equation at: brainly.com/question/2972832

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8 0

3 years ago

Pierre cut the length of an 8 cm wide plank into nine pieces and arranged them as shown in the picture. The centrepiece is a squ

kow [346]

Answer: 200cm

Step-by-step explanation:

The center Planck is a square of length 8cm.

The 4 next planks are of 16 cm each

And the next 4 Planks are of 32 cm each.

8 + 4(8×2) + 4(8×4)

8 + 4(16) + 4(32)

8 + 64 + 128

200 cm

Length of the original plank is 200cm

8 0

3 years ago