Let 4sinx + 3cosx = R sin(x + a) = Rsinxcosa + Rcosxsina
equating coefficients of sinx and cosx:-
RcosA = 4 ......(1)
RsinA = 3.......(2)
So
tan A = 3/4 and A = 36.87 degrees
Find R by squaring and adding (1) and (2)
25 = R^2
R = 5
so we have 5sin(x + 36.87) = 2
sin (x + 36.87) = 0.4
x + 36.87 = arcsin 0.4 = 23.58 degrees
x = - 13.29 degrees
answer is 346.7 degrees
Answer:
Step-by-step explanation:
the way it is written, the answer is
5x^2 - 6x + 2 + 19x - 7
5x^2 + 13x - 5 is the answer.
However I suspect you mean
5x^2 - 6x + 2 + 9x^2 + 10x - 7
14x^2 + 3x - 5 is the answer if the revision I've made is correct.
<u>ANSWER</u>
Extraneous solution: x=6
Real solution: x=11
<u>EXPLANATION</u>
The given expression is
Add -8 to both sides:
Square both sides.
We expand the to get
Write in standard quadratic form.
Factor to get:
We check for extraneous solutions by substituting each value of x into the original equation.
When x=6
Hence x=6 is an extraneous solution.
When x=11
This statement is true.
Hence x=11 is the only solution.
OK so the answer is 0.4 times 1.8 equals 0.72
The answer should be a total of 3