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shtirl [24]
3 years ago
15

Given the enthalpies of reaction

Chemistry
1 answer:
Tju [1.3M]3 years ago
5 0

2SO₂+O₂⇒2SO₃  ΔH=-197 kJ

<h3>Further explanation</h3>

Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways

Reaction

2SO₂+O₂⇒2SO₃

Given :

1. S(s)+O₂(g)→SO₂(g) ΔH = -297 kJ

Reverse

SO₂(g) ⇒S(s)+O₂(g ΔH = +297 kJ (sign change to +) x 2

2SO₂(g) ⇒2S(s)+2O₂(g ΔH =  +594 kJ

2.2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ

Add both reactions and remove/subtract the same compound for different sides

1. 2SO₂(g) ⇒2S(s)+2O₂(g) ΔH =  +594 kJ

2.2S(s)+3O₂(g)→2SO₃(g) ΔH=-791kJ

--------------------------------------------------------+

2SO₂+O₂⇒2SO₃  ΔH=-197 kJ

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Explanation:

From the question we are told that

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3 years ago
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