Answer:
The annual growth rate between 1985 and 2005 is 0.95%
The value of the house in the year 2010 is $152,018
Step-by-step explanation:
Let the annual growth rate = r
Value of the house in year 1985 = $120,000
Value of the house in year 2005 = $145,000
Time (t) = 2005 - 1985
= 20 years
A = P (1 + r)^t
145000 = 120000 (1 + r) ^20
(1 +r)^20 = 145000 / 120000
(1 +r)^20= 1.2083
(1 +r)^20= (1.2083)^1/20
(1 +r)^20= 1.0095
r = 1.0095 - 1
r = 0.0095
r% = 0.0095 x 100
= 0.95%
Value of the house in year 2010
=145000(1 + r)^5
=145000 (1 + 0.0095)^5
= 145000 x 1.0484
=$152,018
Answer:
72000
Step-by-step explanation:
Multiply 120,000 by 0.6 OR multiply 120,000 by 0.4 and subtract 120,000 by the product.
Both equal 72,000
Hope this helps my fellow mike winsowski memer
-Scorpio
Answer:
im quite confused with the way its been layed out
cant tell if ur multiplying of its a X
Step-by-step explanation:
(2^8 times 5 ^-8 times 1) ^-2x times 5^-2 over 2^3 times 4 times 2 ^28
(2^-16x times 5^10x times 5^-2 over 8 times 4 times 2^28
2^16=28 times 5 ^10x
------------------------------- over
50
I don’t know what the formula stands for but if it was in years instead of months I could totally answer
Answer:
96 employees
Step-by-step explanation:
Given that the standard deviation = 22.8
The width in the question = 12
We solve for the margin of error E.
E = width / 2
= 12/2 = 6
At 99%
Alpha = 1-0.99
= 0.01
Alpha/2 = 0.01/2 = 0.005
Z0.005 = 2.576
Sample size n
= ((2.576x22.8)/2)²
= 95.8
= 96
The number of employees is 96
Thank you!
