The first 5 outputs are:
![\begin{array}{c|c}x&2^x\\1&2\\2&4\\3&8\\4&16\\5&32\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Dx%262%5Ex%5C%5C1%262%5C%5C2%264%5C%5C3%268%5C%5C4%2616%5C%5C5%2632%5Cend%7Barray%7D)
As you can see, the outputs keep doubling each time we increment x by 1.
This can be written formally, observing that if you know the value of
, the next value will be
![2^{x+1}=2^x\cdot 2](https://tex.z-dn.net/?f=2%5E%7Bx%2B1%7D%3D2%5Ex%5Ccdot%202)
So, again, we've shown that the next value is twice the previous one, so you have
![g(16)=2g(15)](https://tex.z-dn.net/?f=g%2816%29%3D2g%2815%29)
Answer:
3 mph
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
Answer: B
Step-by-step explanation:
399,499.
Since we are rounding to the nearest thousand, we are going to be focusing on mainly 39(9,499). The rule I learned is, "5 or above, give it a shove". Since it isn't 500 or above, we have to round it down to 9,000.
The total is 399,000.