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skad [1K]
3 years ago
13

A. Write a Python program to match key values in two dictionaries. Input: {'key1': 1, 'key2': 3, 'key3': 2}, {'key1': 1, 'key2':

2} Output: key1: 1 is present in both x and yB. Write a Python program to sort Counter by value. Input: {'Math': 81, Physics':83, 'Chemistry':87) Output: [('Chemistry', 87), ('Physics', 83), ('Math', 81)
Computers and Technology
1 answer:
KIM [24]3 years ago
8 0

Answer:

Please find the attachment of the code file and its output:

Explanation:

In the first code, two variable "a, b" is defined that holds dictionary value which is defined in the question, in the next step a for loop is declared that hold dictionary key and value and use a method set to check the value is available in the dictionary and use print method to print its value.

In the second code, a package counter is an import as the c for count value, in the next step a variable a is declared, that uses a counter method to hold a dictionary value in its parameter, and in the print method, it uses sort method to print its value.

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Decision support systems (or DSSs) model information using OLAP, which provides assistance in evaluating and choosing among diff
Rus_ich [418]

Answer:

C

Explanation:

Decision Support Systems (DSSs) model information using OLAP, helps in providing assistance to evaluate and choose among different course of action.

For option A, an insurance company using DSS to evaluate risk of providing insurance to drivers who doesn't have perfect records and option B and D medical doctor entering symptoms into a system to aid in diagnosing and treating patients and dentist entering symptoms into a system to help diagnose and treat patients respectively

3 0
3 years ago
Write 2-3 lines about the Basic operations of computer
crimeas [40]

Answer:

1. A computer is a machine that carries out arithmetic and logical operations. 2. A computer has two main components- hardware and software. 3. internet runs on computers,

connecting billions of computers the world over

6 0
3 years ago
How to find no of Distinct triangles in a polygon?
8_murik_8 [283]
Input : N = 6
Output : 6 2
The image below is of a triangle forming inside a Hexagon by joining vertices as shown above.
The triangle formed has two sides (AB and BC) common with that of a polygon. Similarly BC and
CD can make one triangle. With this, we can say that there will be a total of 6 triangles possible
having two sides common with that of a polygon. The second image of a hexagon,
a triangle is formed with no side common with that of a polygon.
There will be just 2 triangles possible, BFD and ACE.


Triangle with two side common and no side common of the Hexagon

Number of triangles formed are 6 and 2 with two side common and with no side common respectively.
Input : N = 7
Output : 7 7
7 0
3 years ago
This code --> plt.plot(x,y) is used to draw :
trasher [3.6K]

Answer:

We’ll now take an in-depth look at the Matplotlib tool for visualization in Python. Matplotlib is a multiplatform data visualization library built on NumPy arrays, and designed to work with the broader SciPy stack. It was conceived by John Hunter in 2002, originally as a patch to IPython for enabling interactive MATLAB-style plotting via gnuplot from the IPython command line. IPython’s creator, Fernando Perez, was at the time scrambling to finish his PhD, and let John know he wouldn’t have time to review the patch for several months. John took this as a cue to set out on his own, and the Matplotlib package was born, with version 0.1 released in 2003. It received an early boost when it was adopted as the plotting package of choice of the Space Telescope Science Institute (the folks behind the Hubble Telescope), which financially supported Matplotlib’s development and greatly expanded its capabilities.

Explanation:

6 0
3 years ago
Premise: Tracy has a file that contains a list of actors and the movies in which they acted. She wants to know the top 3 ranked
anzhelika [568]

Answer:

see explaination

Explanation:

Python version : 2.7

Python program to read an input file with specified number of records to read

and output the top 3 ranked actors

The format of input file:

<number of records to read>

<actor_name>,<movie_name>

<actor_name>,<movie_name>

....

'''

#define the file name

filename = 'actors_movies.txt'

# create an empty dictionary to contain the actor name as key and number of movies they have acted as value

actors_movie_count = {}

# open the flie

fp = open(filename)

line = fp.readline() # read the first line

count = int(line)

i = 0

# loop to read count number of lines from file

while i < count:

line = fp.readline() # read a line

data = line.split(",") # split the input data into list of strings using comma as the delimiter

# check if actor name is present in the dictionary, then add 1 to its value

# strip is used to remove any leading or trailing space

if data[0].strip() in actors_movie_count:

actors_movie_count[data[0].strip()] += 1

else: # else insert a new record with actor name as its key and 1 as value

actors_movie_count[data[0].strip()] = 1

i += 1

# close the file

fp.close()

# get the list of names of actors and list of number of movies they have acted

actors = actors_movie_count.keys()

num_movies = actors_movie_count.values()

# loop to sort the actors list and num_movies list in descending order of count of movies

for i in range(len(num_movies)-1):

max = i

for j in range(i+1,len(num_movies)):

if num_movies[j] > num_movies[max]:

max = j

if max != i:

actors[max], actors[i] = actors[i], actors[max]

num_movies[max], num_movies[i] = num_movies[i], num_movies[max]

# rank the actors to add top 3 ranked actors to rank_actors list

rank = 1

rank_actors = []

# add the first actor to list

rank_actors.append(actors[0])

# loop from second to end of actors list

for i in range(1,len(actors)):

# if this actor has same number of movies as the actor before him, then assign same rank

if num_movies[i] == num_movies[i-1]:

# if rank <= 3, add the actor in rank_actors list

if rank <= 3:

rank_actors.append(actors[i])

else: # rank > 3, exit the loop

break

else: # assign 1 more rank that the previous

rank += 1

# if rank <= 3, add the actor in rank_actors list

if rank <= 3:

rank_actors.append(actors[i])

else: # rank > 3, exit the loop

break

# loop to display the top 3 ranked actors

for actor in rank_actors:

print(actor)

#end of program

see attachment for the program screenshot and output

5 0
3 years ago
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