Answer:
The value of x would be 
Step-by-step explanation:
Given,
The dimension of the cardboard = 10 ft by 10 ft,
∵ After removing four equal squares of size x ( in ft ) from the corners,
The dimension of the resultant box would be,
Length = ( 10 - 2x ) ft,
Width = ( 10 - 2x ) ft,
Height = x ft,
The volume of box,
Differentiating with respect to x,
Again differentiating with respect to x,
For maxima or minima,
By quadratic formula,
For x = 5/3, V'' = negative,
While for x = 5, V'' = Positive,
Hence, the value of x would be 5/3 ft for maximising the volume.
So what we know from that is that angle is 30 degrees south of west. so you go 30 degrees down from west. How can we do this? well <span>basically what you have to do is to break down the force into x and y component. The y component of large force and the y component of small force should cancel so that the boat doesn't go north and south and the x components of both the forces should add up so that it goes west only.</span>
Answer:
54 minutes
Step-by-step explanation:
From the question, we are given;
- A room with dimensions 5.2 m by 4.3 m by 2.9 m
- The exchange air rate is 1200 L/min
We are required to determine the time taken to exchange the air in the room;
First we are going to determine the volume of the room;
Volume of the room = length × width × height
= 5.2 m × 4.3 m × 2.9 m
= 64.844 m³
Then we should know, that 1 m³ = 1000 L
Therefore, we can convert the volume of the room into L
= 64.844 m³ × 1000 L
= 64,844 L
But, the rate is 1200 L/min
Thus, time = Volume ÷ rate
= 64,844 L ÷ 1200 L/min
= 54.0367 minutes
= 54 minutes
Therefore, it would take approximately 54 minutes
Answer:
c. x21 + x22 + x23 less or equal than 2800 y2
Step-by-step explanation:
The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.
