Question

Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

Answer 1

Answer:

$P(x,y) = (0,\frac{11}{5})$

Step-by-step explanation:

Given

$A = (-2,1)$

$B = (3,4)$

$m:n = 2:3$

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:

$P(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

Where

$(x_1,y_1) = (-2,1)$

$(x_2,y_2) = (3,4)$

$m:n = 2:3$

This gives:

$P(x,y) = (\frac{2 * 3 + 3 * -2}{2 + 3},\frac{2 * 4 + 3 * 1}{2 + 3})$

$P(x,y) = (\frac{6 - 6}{5},\frac{8 + 3}{5})$

$P(x,y) = (\frac{0}{5},\frac{11}{5})$

$P(x,y) = (0,\frac{11}{5})$