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3 years ago

In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?

Mathematics

2 answers:

WINSTONCH [101]3 years ago

7 0

Answer:

Solution given:

we have

<Q=90°

OP=hypotenuse [h]=89

base[b]=QP=39

perpendicular [p]=OQ=80

we have

cosecant <P=h/p=OP/OQ=89/80

Serjik [45]3 years ago

3 0

Answer:

cos(O) = 39 / 89

Step-by-step explanation:

Given:

ΔOPQ, where

∠Q=90°

PO = 89

OQ = 39

QP = 80

cosine of ∠O?

cos(O) = Adjacent / Hypotenuse

cos(O) = 39 / 89

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