In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?
2 answers:
Answer:
Solution given:
we have
<Q=90°
OP=hypotenuse [h]=89
base[b]=QP=39
perpendicular [p]=OQ=80
we have
cosecant <P=h/p=OP/OQ=89/80
Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
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