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zavuch27 [327]
3 years ago
10

Find the area. Will mark Brainliest.

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer:

63.86

Step-by-step explanation:

Area = 10.3 x 6.2

kobusy [5.1K]3 years ago
4 0

Answer:

I believe the answer is 63.86

Step-by-step explanation:

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CAN SOMEONE PLEASE HELP!!!
IceJOKER [234]

Answer:

162 and 18

Step-by-step explanation:

use fractions make x 180 and do 9/10x and 1/10x

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2 years ago
F(h) = -2(h - 4)2 + 22.​
Ivenika [448]
Here’s what I found that can help you step by step

5 0
3 years ago
36.00x0.07 show explanation
makkiz [27]

Answer: 2.52

Step-by-step explanation: 36.00x0.07

36.00 is the same as 36

so, 36x0.07=2.52

5 0
2 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
3 years ago
Find the length of CA to the nearest tenth of a foot
hoa [83]

Answer:

CA ≈ 3.1 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan40° = \frac{opposite}{adjacent} = \frac{BC}{CA} = \frac{2.6}{CA} ( multiply both sides by CA )

CA × tan40° = 2.6 ( divide both sides by tan40° )

CA = \frac{2.6}{tan40} ≈ 3.1 ft ( to the nearest tenth )

3 0
3 years ago
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