Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
148 square inches
Step-by-step explanation:
Step 1: finding the area of the base (upper base plus lower base)
2( L x W).
2 (6in. x 5in.)
2( 30 square inches.)
60 square inches
Step 2: finding the area of first 2 sides
2 ( l x w)
2 ( 5in x 4in)
2 ( 20 square inches.)
40 square inches
step 3: finding the area of the last 2 sides
2(lxw)
2(4in.x 6in.)
2(24 square inches.)
48 square inches
step 4: combine all the answers.
60 square inches. + 40 square inches. + 48 square inches = 148 square inches
Answer:
x^2-12x+27
Step-by-step explanation:
(x-3)(x-9)=x^2-3x-9x+27=x^2-12x+27
X= 1/2 or x = 3/2.
Step 1: factor left side of equation. (2x-1)(2x-3)=O
Step 2: Set factors equal to 0. 2x-1=0 or 2x-3=0
X= 1/2 or x = 3/2.
