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liberstina [14]
3 years ago
12

Can you please answer this for me thank you​

Mathematics
1 answer:
Katarina [22]3 years ago
3 0

Answer:

?????????

I am sorry but I don't know the answer

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luda_lava [24]
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Simplify 3(2x - 5). whats the answer?
Irina18 [472]

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In right triangle ABC shown below, the midpoint of hypotenuse AC is located at D and segment BD is drawn.
Allisa [31]

9514 1404 393

Answer:

  diagonal AC is 20, so all half-diagonals are 10. BD is one such.

Step-by-step explanation:

The length of hypotenuse AC is given by the Pythagorean theorem:

  AC² = AB² + BC²

  AC² = 12² +16² = 400

  AC = √400 = 20

The midpoint of AC is 10 units from A and from C.

Consider point E that finishes rectangle ABCE. Then diagonals BE and AC meet at their midpoints, D. The diagonals of a rectangle are the same length, so the four half-diagonals are congruent:

  AD = CD = ED = BD = 10

_____

<em>Alternate solution</em>

The "rise" from BC to D is half of AB, so is 6.

The "run" from AB to D is half of BC, so is 8.

The Pythagorean theorem tells you BD = √(6² +8²) = 10.

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vlabodo [156]

Answer:

11

Step-by-step explanation:

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