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bixtya [17]
3 years ago
8

The number 75 can be written as the sum of the squares of 3 different positive integers. what is the sum of these 3 integers? 17

16 15 14 13 next help end review review screen
Mathematics
1 answer:
ioda3 years ago
6 0

75=7^2+5^2+1^1\\\\ 7+5+1=13

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Ken Has Two Red Shirts, Two Blue Shirts, A Pair Of White Pants And A Pair Of Blue Pants. The Probability That He Will Wear A Red
insens350 [35]

There is a 2 in 4 chance for a red shirt

there is a 1 in 2 chance for blue pants

There is (I think) a 1 in 6 chance for the chosen pain to be worn.

8 0
3 years ago
Grayson went to the grocery store and bought bottles of soda and bottles of juice. Each bottle of soda has 35 grams of sugar and
Illusion [34]

The number of bottles of soda purchased is 10 and the number of bottles of juice purchased is 4.

<u>Step-by-step explanation:</u>

Let us consider the soda bottles as x and juice bottles as y.

From the given data we can derive 2 equations,

35x+15y= 410.    .....(1)

x=y+6.                 ....(2)

Substitute equation (2) in (1),

35(y+6)+15y=410.

35y+ 210+15y=410.

50y+210=410.

50y=410-210.

50y=200.

y=4.

Substitute y value in equation (2),

x=4+6.

x=10.

The number of bottles of soda purchased is 10 and the number of bottles of juice purchased is 4.

4 0
2 years ago
You and your friend are painting the walls in your apartment. You estimate that there is 1000 square feet of space to be painted
leva [86]
After 45 minutes you will have painted 4*45=180 square feet.

so the total number of painted area, y, is:

y=180+x*(3+4) after the 45 minutes

where x is the number of minutes AFTER THE 45 minutes:

if y is 1000 then

1000=180+x*7
820=x*7
x=117.14

so 117 minutes, or one hour and 57 minutes.
5 0
2 years ago
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
3 years ago
Iwould like the answer and the details on a paper
PilotLPTM [1.2K]
I can't download the picture, you will have to type it out so I can explain it

5 0
3 years ago
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