b. The fault is younger than the layers it cuts through, but older than the layers above it.
Explanation:
Since the fault cuts through the lower rock layers and terminates against the ones above it, we can conclude that the fault is younger than the layers it cut through but older than the layers above it.
We know this based on the principle of cross-cutting.
The principle of cross-cutting relationship suggests that "a fault and an intrusion is younger than the rocks they cut through".
- This principle is very important in determining the relative age of sedimentary strata.
- The rock units through which a fault permeates must have been there before the fault formed. So they are older.
- If the overlying layer above the fault is not affected then it is younger than the faulting event
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Answer:
Explanation:
Given data:
exhaust velocity = 2.455 km/s
specific impulse = 294 second
Ve = effective exhaust velocity
Isp specific impulse
g_o = standard gravity
from above equation we have
![\frac{mo}{mi} = e^{\frac{\Delta v}{Ve} [tex]\frac{mo}{mi} = e^{\frac{2455}{2881.2}](https://tex.z-dn.net/?f=%5Cfrac%7Bmo%7D%7Bmi%7D%20%3D%20e%5E%7B%5Cfrac%7B%5CDelta%20v%7D%7BVe%7D%3C%2Fp%3E%3Cp%3E%20%5Btex%5D%5Cfrac%7Bmo%7D%7Bmi%7D%20%3D%20e%5E%7B%5Cfrac%7B2455%7D%7B2881.2%7D)
[ 2.455 km/s = 2455 m/s]
