4 years ago

Prove that opposite sides of a parallelogram are congruent.

Mathematics

1 answer:

ad-work [718]4 years ago

6 0

Side angle side or SAS

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$a + b \geq 30$

$b - a \geq 10$

Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

$a + b \geq 30$

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

$b - a \geq 10$

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

$a + b \geq 30$

$b - a \geq 10$

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