Answer:
x = 5
y = 11
Step-by-step explanation:
y = 4x - 9
2x -3(4x - 9) = -23
2x - 12x + 27 = -23
-10x = -23 -27
-10x = -50
minus cancels out
x = 5
y = 4(5) -9
y = 20 - 9
y = 11
Answer:
Total wrapping papers Serena and her grandmother = 51/10
Step-by-step explanation:
Serena's wrapping paper for parents:
- sq meters
Grandmother's wrapping paper:
- sq meters
In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.
i.e.
Total papers = Serena's wrapping paper + Grandmother's wrapping paper
Therefore, total wrapping papers Serena and her grandmother = 51/10
Answer:
6xy²z^4
Step-by-step explanation:
= ∛(6³)(x³)(y³)(y³)(z³)(z³)(z³)(z³) = 6x·y·y·z·z·z·z = 6xy²z^4
$7.20
(Seven Dollars and Twenty Cents)
Answer:
Adult Ticket Price = $13
Child Ticket Price = $13
Step-by-step explanation:
Let price of adult ticket be "a" and child ticket be "c"
13 adult and 14 child equals $351, so we can write:
13a + 14c = 351
and
2 adult and 7 child equals $117, thus we can write:
2a + 7c = 117
We multiply 2nd equation by (-2) to get:
-2 * [2a + 7c = 117]
= -4a -14c = -234
Adding botht he "bold" equations, we get:
13a + 14c = 351
-4a -14c = -234
------------------------
9a = 117
a = 117/9 = 13
Now to find b, we use the value of a gotten in the first equation:
13a + 14c = 351
13(13) + 14c = 351
169 + 14c = 351
14c = 182
c = 182/14 = 13
Hence,
<em>Adult Ticket Price = $13</em>
<em>Child Ticket Price = $13</em>