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2 years ago

9

During summer, the height of the water in a pool decreased by 2 inches each week due to evaporation. What is the change in the h

eight of the water over an 8 week period??

1 answer:

Alecsey [184]2 years ago

8 0

Answer:

16in or 1ft 4in

Step-by-step explanation:

You might be interested in

The air temperature is -6 degrees celsius every hour for several hours. The air temperature after x hours is represented by the

andreyandreev [35.5K]

Answer:

x-intercept is (2,0) [The x-intercept means that it takes 2 hours for the temperature to reach 0°C]

y-intercept is (0, -6) [The y-intercept represents the temperature at sunrise, -6°C]

Step-by-step explanation:

<u>Complete Question:</u>

<em>The air temperature is -6 degrees celcius at sunrise and rises 3 degree celcius every hour for several hours. The air temperature after x hours is represented by the function f(x) = 3x - 6. Find the x-intercept and y-intercept and interpret their meaning.</em>

<em />

The x-intercept is the x-axis cutting point found by setting y = 0 [function = 0]
The y-intercept is the y-axis cutting point found by setting x = 0

Lets find x-intercept first:

f(x) = 3x - 6

0 = 3x - 6

3x = 6

x = 6/3

x = 2

x-intercept is (2,0)

Now, lets find y-intercept:

f(x) = 3x - 6

f(x) = 3(0) - 6

f(x) = -6

y-intercept is (0, -6)

The x-intercept means that it takes 2 hours for the temperature to reach 0°C

The y-intercept represents the temperature at sunrise, -6°C

3 0

2 years ago

Determine the number of solutions that exist to the equation?

IceJOKER [234]

Many when you solve it it works out perfectly.

6 0

2 years ago

Which of the following is NOT one of the three major credit bureaus?

vovangra [49]

What are the options ?

3 0

2 years ago

What does s equal?pls help me plsss.

Archy [21]

Answer:

s< -7/11

Step-by-step explanation:

6 0

2 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago