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3 years ago

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What are the short-run equilibrium values of Y, r, Y – T, C, I, private saving, public saving, and national saving? Check by ens

uring that C + I + G = Y and national saving equals I.

1 answer:

svetlana [45]3 years ago

6 0

Answer:

[AD = C + I + G] = [AS = Y]

S = I

Explanation:

Economy is at equilibrium when : Aggregate Demand = Aggregate Supply

Aggregate Demand [AD] is the total value of goods & services, all sectors of an economy are planning to buy, during a period of time.

Assuming 3 sector Economy having : Households, Firms, Government

AD = Consumption (C) + Investment ( I ) + Net Govt. Expenditure (NG = G-T)

Aggregate Supply [AS] is the total value of goods & services, all producers of economy are planning to sell, during a period of time. Total value of goods & services is distributed among all production factors as factor incomes. And, Income is either saved or consumed.

AS = National Income [ Y ] = Consumption (C) + Saving (S)

So, Equilibrium : [AD =C + I + NG] = [ AS = Y] → ∴ C + I + NG = Y

[AD = C + I + NG] = [ AS = C + S] → ∴ C + I + NG = C + S

Assuming : leakage (tax) = injection (govt expenditure) ; NG = G-T = 0

So, C + I = C + S → ∴ I = S

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Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

Radda [10]

Answer:

$1170839.28 dyn/cm^2$

16.9816 psia

$117.083928 kN/m^2$

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

$P_{abs}=P_{atm}+P_G$

And the gauge pressure is given by the contributions of columns of water ( $P_{w}$ ) and mercury( $P_{Hg}$ ), we can calculate the contribution of each column as:

$P= \rho g h$ (*)

where $\rho$ is the respective density, g gravity and h is height.

So we have all the data required to use the above equations ( $P_{atm}$ , height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( $P_{atm}$ , $P_{w}$ and $P_{Hg}$ ). Note that the units "x" mmHg means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

$mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}$

$mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O$

And pressure of water in mmHg is

$0.0737*56=4.1246 mmHg$

The absolute pressure is:

$P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246 = 881.1246 mmHg = 88.11246cmHg$

To pass to dyn/cm^2 units we need to use the equation (*)

$P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}$

Note: We need to use cm Hg for units coherence

Now passing from dyn/ $cm^2$ to kN/ $m^2$ (or kPa) we need to consider that 1 dyn is $10^{-8}$ kN and 1 $cm^2$ is $10^{-4} m^2$ .

$1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2$

Now passing kN/ $m^2$ to psia. We need to consider that 1 psia is 6.89476.

$117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia$

8 0

3 years ago

Gloria is a tax accountant who is very busy from january to april 15, which is the tax return filing deadline. she feels that sh

matrenka [14]

Gloria is encountering pressure. In spite of the fact that uneasiness might be an aftereffect of weight, Gloria is encountering weight subsequently of her need to work longer hours to meet a due date.

I hope the answer will help you.

8 0

3 years ago

An analyst asked to perform a TCO analysis for a system would need to take into account

balu736 [363]

Can you dm me for the answer I’m not home rn I’m trying to help out a lot of people

4 0

3 years ago

Jolene is the network administrator at the bank. In 2-5 sentences, describe what she does in this position.

Schach [20]

A network administrator is a person who maintains the network and information system infrastructure in a company. Jolene would likely do the same job description. She keeps updated with the system requirement at the bank to provide every transaction without a problem. She maintains and controls the network and information system at the bank to ensure there is no system problem<span>.</span>

5 0

3 years ago

The following transactions occurred during December 31, 2021, for the Falwell Company. A three-year fire insurance policy was pu

Leya [2.2K]

Answer

The answer and procedures of the exercise are attached in the following archives.

Explanation

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

1. Insurance expense for 6 months = 12,960 x 6/36

= $2,160

Prepaid insurance on December 31, 2021 = 12,960 - 2,160

= $10,800

2.Interest expense for 2 months = 220,000 x 12% x 2/12

= $4,400

Kindly comment if you need further assistance. Thanks

7 0

3 years ago