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➷ I'm assuming the answer is to be left in algebraic form.
Perimeter = length + length + width + width or (2 x length) + (2 x width)
Substitute the values in:
Perimeter = 2(3x - 5y - 4z) + 2(x - 3y + 5z)
Simplify:
Perimeter = 6x - 10y - 8z + 2x - 6y + 10z
Perimeter = 8x - 16y + 2z <== this is the answer
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➶ Hope This Helps You!
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Answer:
Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Step-by-step explanation:
In order to determine if the poster will lie flat in the box or not, we will determine the length of the sides of the poster and the box, if the length of the side of the square poster is smaller than that of the box, it will lie flat. This is calculated as follows:
Area of poster = 4 square feet
Area of poster = (Length)²
4 = (Length)²
∴ Length = √(4)
Length of poster = 2 Ft
Volume of box = 14 cubic feet
Volume of box = (Length)³
14 = (Length)³
∴ Length = ∛(14)
Length = 2.41 Ft
∴ Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
The answer is 2 because if the variable or numbers are close together you have to multiply those 2 numbers so that means it would look like this ---> XY=10=5 X 2=10. :)
Answer:
30√3 ≈ 51.96 miles
Step-by-step explanation:
The distance between the two ships can be found using the Law of Cosines, or using your knowledge of the side relationships in special triangles.
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Each ship is traveling at 10 mph, so after 3 hours will have traveled 30 miles.
The triangle OS1S2 formed by the harbor and the two ship locations is an isosceles triangle with base angles of 30°. Each half of OS1S2 is a 30-60-90 triangle whose longer leg is √3 times half the hypotenuse. The sum of those two "longer legs" is the distance between the ships.
The distance between ships is 2×15√3 = 30√3 ≈ 51.96 miles.
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<em>Additional comment</em>
If you prefer to use the Law of Cosines, you are looking for the length of the side opposite the 120° angle in a triangle with sides of 30 miles.
c² = 30² +30² -2·30·30·cos(120°) = 30²(2-2·(-0.5)) = 3·30²
c = 30√3 . . . . . take the square root (miles)