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rjkz [21]
2 years ago
9

Im very confused about my precourse work for AP environmental science.

Mathematics
1 answer:
Nataliya [291]2 years ago
8 0

The computation shows that the values are 64000 acres and 563 metric tons.

<h3>How to compute the values?</h3>

1. A 100 square mile area of national forest is how many acres?

1 mile square = 640 acres

100 square miles = 100 × 640 = 64000 acres.

2. Fifty eight thousand kilograms of solid waste is equivalent to how many metric tons?

1 metric ton = 103kg

58000 kg = 58000/103 = 563 metric tons

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

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Please solve these equations much appreciated
Reptile [31]

Answer:      

Part c) V=16,500\ m^3

Part d) V=93,312\pi\ mm^3  or V=292,999.68\ mm^3

Step-by-step explanation:

Part c) Find the volume of the inverted rectangular pyramid

The volume of the rectangular pyramid is equal to

V=\frac{1}{3}Bh

where

B is the area of the rectangular base

h is the height of pyramid

<em>Find the area of the base B</em>

B=(60)(15)=900\ m^2

h=55\ m

substitute

V=\frac{1}{3}(900)(55)

V=16,500\ m^3

Part d) Find the maximum volume of tea in the tea cup

we know that

The volume of cylinder (tea cup) is equal to

V=\pi r^{2}h

we have

r=36\ mm\\h=72\ mm

substitute

V=\pi (36)^{2}(72)

V=93,312\pi\ mm^3 -----> exact value

<em>Find the approximate value</em>

assume

\pi =3.14

V=93,312(3.14)=292,999.68\ mm^3

7 0
3 years ago
I don't get question a
Maslowich
Enlarge means to make bigger
3 0
3 years ago
2. A birthday party host planned for 20 people,
nataly862011 [7]
3% Because if you would subtract the number of people that were invited and the number of people that only came, it would give you a total of 3% (hope that helped a little?)
4 0
3 years ago
Please hellpppp me I’m stuck
Ber [7]

Answer:

Triple the length, height and width

8 0
3 years ago
What is the focus of the parabola given by -1/4(y+2)^2=(x-1)
AleksandrR [38]
\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}}) }\\\\&#10;(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\

\bf -\cfrac{1}{4}(y+2)^2=(x-1)\implies (y+2)^2={-4}(x-1)&#10;\\\\\\\&#10;[y-(-2)]^2=-4(x-1)\quad &#10;\begin{cases}&#10;k=-2\\&#10;h=1\\&#10;4p=-4&#10;\end{cases}\implies 4p=-4\implies \boxed{p=-1}

so, is a horizontal parabola, the "p" distance is 1, however, we ended up with a negative value, that means, the parabola is opening to the left-hand-side, with a vertex at (1, -2), and its focus at 0, -2, like you see in the picture below, one unit to the left of the vertex.

6 0
3 years ago
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