Question

Find the magnitude of the vector v=<-1,3>.√101082√2​

Answer 1

Answer:

√10

Step-by-step explanation:

Magnitude of a vector:

The magnitude of a vector v = <a,b> is given by:

$|v| = \sqrt{a^2 + b^2}$

v=<-1,3>

Then:

$|v| = \sqrt{(-1)^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10}$

$\sqrt{10}$ is the magnitude of the vector.