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2 years ago

Find the magnitude of the vector v=<-1,3>.√101082√2

Mathematics

1 answer:

Dmitrij [34]2 years ago

8 0

Answer:

√10

Step-by-step explanation:

Magnitude of a vector:

The magnitude of a vector v = <a,b> is given by:

$|v| = \sqrt{a^2 + b^2}$

v=<-1,3>

Then:

$|v| = \sqrt{(-1)^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10}$

$\sqrt{10}$ is the magnitude of the vector.

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Find the magnitude of the vector v=<-1,3>.√101082√2​

Find the magnitude of the vector v=<-1,3>.√101082√2