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Kitty [74]
2 years ago
13

What is the area of the shape below? (picture below) please solve!

Mathematics
1 answer:
Oliga [24]2 years ago
4 0
Answer: 18 i think explanation:
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Solve for x? Please
sasho [114]
Check the picture below.

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3 years ago
Jaelynn has 30 times as many stikers as her brother her brother in has 8 stikers how many stikers does jaelynn have
Andre45 [30]

30 × 8 = 240 is the answer

6 0
3 years ago
Here's a easy one<br> Not accepting links!
irakobra [83]
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5 0
3 years ago
A red light
ANEK [815]

Answer:

Both lights would flash together after every 30 seconds.

Step-by-step explanation:

6 = 2 * 3 and 10 = 2 * 5.

LCM (Least Common Multiple) of 6 and 10 = 2 * 3 * 5 = 30.

Therefore, both lights wold flash together after every 30 seconds.

3 0
3 years ago
The distribution of scores on the SAT is approximately normal with a mean of mu = 500 and a standard deviation of sigma = 100. F
ella [17]

Answer:

a. 2.28%

b. 30.85%

c. 628.16

d. 474.67

Step-by-step explanation:

For a given value x, the related z-score is computed as z = (x-500)/100.

a. The z-score related to 700 is (700-500)/100 = 2, and P(Z > 2) = 0.0228 (2.28%)

b. The z-score related to 550 is (550-500)/100 = 0.5, and P(Z > 0.5) = 0.3085 (30.85%)

c. We are looking for a value b such that P(Z > b) = 0.1, i.e., b is the 90th quantile of the standard normal distribution, so, b = 1.281552. Therefore, P((X-500)/100 > 1.281552) = 0.1, equivalently  P(X > 500 + 100(1.281552)) = 0.1 and the minimun SAT score needed to be in the highest 10% of the population is 628.1552

d. We are looking for a value c such that P(Z > c) = 0.6, i.e., c is the 40th quantile of the standard normal distribution, so, c = -0.2533471. Therefore, P((X-500)/100 > -0.2533471) = 0.6, equivalently P(X > 500 + 100(-0.2533471)), and the minimun SAT score needed to be accepted is 474.6653

4 0
3 years ago
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