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miss Akunina [59]
3 years ago
5

Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8 1. Isolate x in the first equation: 2. Substitute the v

alue for x into the second equation: 3. Solve for y: 4. Substitute y into either original equation: 5. Write the solution as an ordered pair:
Mathematics
2 answers:
Anettt [7]3 years ago
5 0
X + 3y = 7
x = -3y + 7

2x + 4y = 8
2(-3y + 7) + 4y = 8
-6y + 14 + 4y = 8
-6y + 4y = 8 - 14
-2y = - 6
y = -6/-2
y = 3

x + 3y = 7
x + 3(3) = 7
x + 9 = 7
x = 7 - 9
x = -2

solution is (-2,3)
Finger [1]3 years ago
5 0

Answer:

-2,3. I know this because I got it correct on Edge.

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2. A restaurant employs five people. The two cooks work 36 hours
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Answer:

Total amount = R5112

Step-by-step explanation:

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The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
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{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

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Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

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.3456+.2304+.0768= .6528

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