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Aleks [24]
2 years ago
5

You are looking through a microscope at a cell in a phase of cell division. you see a double row of chromosomes lined up at the

equator of the cell. what phase is this cell in?
Biology
1 answer:
aev [14]2 years ago
6 0
The cell is in METAPHASE PHASE OF MEIOSIS.  At this phase, the pairs of homologous chromosomes moves to the cell equator. These pairs of homologous chromosomes will be separated in anaphase I. The number of chromosomes remains constant until the first cell division is completed, then the chromosomes will be divided into two daughter cells. 
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Answer ASAP 50 points
Mnenie [13.5K]

Answer/Explanation:

In humans, we breathe in oxygen via the respiratory system. The oxygen enters the lungs. The air sacs in the lungs - the alveoli - are the site of gas exchange in the lungs and are where the circulatory and respiratory systems interact.

The alveoli take in the oxygen, where it diffuses into the capillaries (circulatory system). Blood, which passes through the capillaries takes this oxygen to all the cells in the body. Oxygen binds to haemoglobin in red blood cells, which transport it around the body.

Additionally, blood also transports carbon dioxide back to the alveoli of the lungs, where it diffuses into the lungs and is expelled when we breathe out

3 0
3 years ago
What is more stable a food chain or food web?
wolverine [178]
I believe that the food web is more stable

8 0
3 years ago
Which of the following does not happen in Interphase?
Nat2105 [25]

Answer:

thye chromosomes are not visible

Explanation:

5 0
3 years ago
Genes A and B are 10 map units apart and genes B and C are 20 map units apart, with gene B located between genes A and C. What w
Marizza181 [45]

Answer:

2% of the progeny will be double crossovers for the trihybrid test cross

Explanation:  

By knowing the positions of genes, we can estimate the distances in MU between them per region.

  • Genes A and B are 10 map units apart (Region I)
  • Genes B and C are 20 map units apart (Region II)
  • Genes A and C are 30 map units apart

----A-------10MU--------B-------------20MU-------------C---

             Region I                      Region II  

We can estimate the recombination frequencies by dividing each distance by 100.

• recombination frequency of A-B region = 10MU / 100 = 0.10

• recombination frequency of B-C region = 20MU / 100 = 0.20

Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:

EDRF = recombination frequency in region I x recombination frequency in region II.

EDRF = 0.10 x 0.20 = 0.02        

2% of the progeny will be double crossovers for the trihybrid test cross

   

7 0
3 years ago
Help please c;
denis-greek [22]
Ok, I'm not fully sure but answer B sound right, so I think it's right
3 0
3 years ago
Read 2 more answers
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