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Troyanec [42]
2 years ago
11

Which one I need help

Biology
1 answer:
sasho [114]2 years ago
5 0
Both of them are correct.

Methane is an explosion hazard in enclosed areas. Liquefied Methane floats on water and boils. The vapor cloud produced is FLAMMABLE

In landfills, the food and yard waste that trash contains is decomposing and releasing methane, a greenhouse gas that's 28 times more potent than carbon dioxide.
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Compared to earth , mercury rotated on its axis very slowly and im wasting my time
Jet001 [13]

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3 years ago
Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m
Vanyuwa [196]
This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

<span>Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
v=\frac{2\pi{r}}{T}
</span>=\frac{2\pi{r}}{1.88*365.25*86400} m/s, accounting for leap years
=3.371*10^{-8}\pi{r}   m/s

The centripetal force, Fc, generated is
Fc=\frac{mv^2}{r}   
        where m=mass of mars = 6.39*10^(24) kg
=\frac{mv^2}{r}
=\frac{6.39*10^{24}v^2}{r}
=7.26168*10^9\pi^2r

The gravitation pull from the sun, Fg, is given by
Fg=\frac{GMm}{r^2}
    where G=grav. const., =6.67408*10^(-11) m^3<span> kg^(</span>-1)<span> s^(</span>-2)
              M=mass of sun=1.989*10^(30) kg
=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}
=\frac{8.4826*10^44}{r^2}

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}
Solving for the real root:
r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}
=\frac{1.1681263*10^{35}}{\pi^2}
=2.279*10^11 m


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the answer is definitly D.)

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They can harm other native species and thrive in the new environment which can potentially make the other species go extinct as the new species has no predators.
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